8[4-(3-4x)]+3x=5(7x+4)-12

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Solution for 8[4-(3-4x)]+3x=5(7x+4)-12 equation: 


Simplifying
8[4 + -1(3 + -4x)] + 3x = 5(7x + 4) + -12
8[4 + (3 * -1 + -4x * -1)] + 3x = 5(7x + 4) + -12
8[4 + (-3 + 4x)] + 3x = 5(7x + 4) + -12

Combine like terms: 4 + -3 = 1
8[1 + 4x] + 3x = 5(7x + 4) + -12
[1 * 8 + 4x * 8] + 3x = 5(7x + 4) + -12
[8 + 32x] + 3x = 5(7x + 4) + -12

Combine like terms: 32x + 3x = 35x
8 + 35x = 5(7x + 4) + -12

Reorder the terms:
8 + 35x = 5(4 + 7x) + -12
8 + 35x = (4 * 5 + 7x * 5) + -12
8 + 35x = (20 + 35x) + -12

Reorder the terms:
8 + 35x = 20 + -12 + 35x

Combine like terms: 20 + -12 = 8
8 + 35x = 8 + 35x

Add '-8' to each side of the equation.
8 + -8 + 35x = 8 + -8 + 35x

Combine like terms: 8 + -8 = 0
0 + 35x = 8 + -8 + 35x
35x = 8 + -8 + 35x

Combine like terms: 8 + -8 = 0
35x = 0 + 35x
35x = 35x

Add '-35x' to each side of the equation.
35x + -35x = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 35x + -35x

Combine like terms: 35x + -35x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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